![]() ![]() Note that this is aligned to 4096 bytes: 250067632 is a multiple of 8 (the sectors contain 512 bytes here, and 8×512 is 4096).ĭepending on how you use the partition, alignment of the end sector might be important for example, if you’re partitioning a 512e disk (a disk which uses 4096-byte sectors internally, but exposes 512-byte logical sectors), and want to use it with cryptsetup and 4096-byte blocks to improve performance ( cryptsetup luksFormat -sector-size=4096), you’ll have to ensure that the partition contains an exact multiple of 4096 bytes (not sectors). Sectors are numbered from 0 fdisk is suggesting the last sector on your disk (which has 250069680 sectors). ![]() Alignment of the start sector affects all the sectors in the partition alignment of the last sector only affects the last few sectors of the partition, if at all. Last sector, +sectors or +size (2048-250069679, default 250069679):Ĭreated a new partition 1 of type 'Linux' and of size 119,2 GiB.ĭevice Boot Start End Sectors Size Id Type P primary (0 primary, 0 extended, 4 free)Į extended (container for logical partitions)įirst sector (2048-250069679, default 2048): I/O size (minimum/optimal): 512 bytes / 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes image creation Create such disk image with Microsoft VirtualPC (tm), Qemu's disk image utility (qemu-img) or bximage utility (see Section 9.22 for more information). ![]() Wouldn't it be better to set the Start and End value to a number that can be divided by 512 or 2048 or 4096?įor example: Start 4096 and End 250068992ĭisk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors The 'vpc' disk image mode is mostly a port of Qemu's 'vpc' block driver for VirtualPC disk images (written by Alex Beregszaszi and Kevin Wolf). I am wondering what Start and End value to choose when partitioning my ext. ![]()
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